# Exercise 1.16 - Print length of arbitrary long input line¶

## Question¶

Revise the main routine of the longest-line program so it will correctly print the length of arbitrary long input lines, and as much as possible of the text.

## Solution¶

```/**
* Exercise 1.16
*
* Write a program to print the length of an arbitrarily long input line
* and as much text as possible
*
**/

#include <stdio.h>

/* The size of the output that we would like */
#define MAX 1000

/* define our functions*/
int get_line(char arr[], int lim);

void copy(char to[], const char from[]);

int main() {

int len, max;
char line[MAX];
char longest[MAX];

max = 0;
while ((len = get_line(line, MAX)) > 0) {

if (len > max) {

max = len;
copy(longest, line);
}
}

if (max > 0) {

printf("length = %i, string=%s", max, longest);
}

return 0;
}

/* get a line in a character array */
int get_line(char arr[], int lim) {

int c, i;

for (i = 0; i < lim - 1 && (c = getchar()) != EOF && c != '\n'; ++i) {

arr[i] = c;
}
if (c == '\n') {

arr[i] = c;
++i;

} else {

/* Continue to count the length even if it is longer than the max */
while ((c = getchar() != EOF) && c != '\n') {

++i;
}

if (c == '\n') {

arr[i] = c;
++i;
}
}

arr[i] = '\0';
return i;
}

/* copy one character array to another */
void copy(char to[], const char from[]) {

int i;

i = 0;

while ((to[i] = from[i]) != '\0') {

++i;
}
}
```

### Explanation¶

A string in C is a character array which ends in 0. getline is a function in our program, which reads one character at a time using getchar and stores it in a character array called s[] and it returns the length of the array.

We keep track of each line and it’s length using a variable, max. If the length of the line is greater than max, then we copy that line into the maxline using a copy routine.

At the end of the program, whichever was the longest line that was copied in maxline array, we just print that.